Question

From 200 mg of co2, 10^21 molecules are removed. how many moles are left?​

Answer 1

Answer:

One mole of atoms =6.023×1023 atoms = Gram atomic mass of element

44 grams of CO2=1moleCO2=6×1023 molecules of CO2

200mg=44×1000200×1moles=44×1000200×1023×6.023 molecular of CO2

=27.37×1020 molecular of CO2

=2.737×1021 molecules of CO2

molecules left =1.737×1021 molecular of CO2

moles of CO2 left =6.023×10231.737×104

=0.29×10−2 moles of CO2

=2.9 mill moles 

Answer 2

Step-by-step explanation

$.$

One mole of atoms 6.023 x 1023 atoms

= Gram atomic mass of element

44 grams of CO2 = 1 mole CO₂ = 6 ×1023 molecules of CO₂

200 mg 200×1 / 44 x 1000 moles =

200 x 1023

_________

44 x 1000 x 6.023 molecular of CO2

= 27.37 × 10²⁰ molecular of CO2

= 2.737 × 10²¹ molecules of CO₂

molecules left = 1.737 × 1021 molecular of CO2

moles of CO₂ left =

1.737 x 104

__________

6.023 x 1023

= 0.29 x 10-² moles of CO2

2.9 mill moles

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