Question

from 200mg of co2 10^21molecule removed how many grams of CO2 are left​

Answer 1

Answer:

125.92

Explanation:

1 mole of CO2 = 44g contains 6.022 x 1023 molecules

Thus 200 mg will contain:

0.244x 6.022 x 1023 = 2.7 x 1021 molecules

After removal of 1021 molecules,

1.7 x 1021 molecules will remain,

As 200 mg contains 2.7 x 1021 molecules, 1.7 x 1021 will weigh

200 x (1.7 x 1021)2.7 x 1021 = 125.92 mg