from 200mg of co2 10^21molecule removed how many grams of CO2 are left
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total molecules are 200/44*6.022*10^23 it is approx 10^25*3/11
after removing 10^21 molecule
molecules left are=10^25-10^21
=9999*10^21
Now grams=44*9999*10^21*3/11/6.022*106^23
=So the value will be 199.988 gm
arslaan17:
i got the answer 1.3×10^21....can u please check it
so answer will be 199.988 mg
moles=given mass/malr mass that is 0.2/avagadros no
correct me if i m wrong
moles=200/46
moles=0.2/44
sorry you are right
is my answer rigjt then??
moles=.2/44
but i think my answer is right as both times moles will be cutted
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