From 200mg of Co2 when X molecules are removed, 2.89*10-3 moles of CO2 are left. X will be
Answers
Answer:
Explanation:
2
Answer: 10^21 molecules of CO2
Explanation: We have 200 mg of carbon dioxide. The molar mass of carbon dioxide is 44g. That is there are 6.022 × 10^23 molecule of CO2 in 44g of CO2.
Thus, number of moles of CO2 in 44g of CO2 = 1
number of moles of CO2 in 1g of CO2 = 1 / 44
number of moles of CO2 in 200 mg or 200 × 10^-3 g of CO2
= (1 × 200 × 10^-3) / 44
= 4.545 × 10^-3 moles
We are given that after removing X molecules from 200 mg of CO2, 2.89 X 10^-3 moles of CO2 are left.
Therefore, number of moles of CO2 removed will be
= total number of moles of CO2 - number of moles of CO2 left
= 4.545 × 10^-3 - 2.89 × 10^-3
= 1.655 × 10^-3 moles of CO2
Thus, 1.655 × 10^-3 moles of CO2 were removed. The number of molecules X can be calculated by simply multiplying this quantity with Avogadro's number.
So, number of CO2molecules removed will be
= 1.655 X 10^-3 X 6.022 X 10^23
= 9.969 X 10^20 molecules of CO2
=10 X 10^20 molecules of CO2
=10^21 molecules of CO2