Question

from 22 gm of CO2,2×10^23 molecules are removed.how many grams and moles of CO2 are left

Answer 1

44g of CO2 = 1 mole=6 ×10^2²³ molecules

22gm CO2=0.5mole=3×10^²³ molecules

If 2×10^²³ molecules removed remain will be= 1×10^²³=1/6 mole=7.34gm

Answer 2

Answer:

From 22 gm of CO2,2×10^23 molecules are removed.how many grams and moles of CO2 are left .

22gm CO2=0.5mole= 3×10^²³ molecules. If 2×10^²³ molecules .

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