Question

from 22 gm of CO2, 3×10^22 molecules are removed.how many grams and moles of CO2 are left

Answer 1

Answer:

44g of CO2 = 1 mole=6 ×10^2²³ molecules

22gm CO2=0.5mole=3×10^²³ molecules

If 2×10^²³ molecules removed remain will be= 1×10^²³=1/6 mole=7.34gm

Answer 2

Answer:

The amount of CO₂ and the moles of CO₂ left is 20.17 grams and 0.46 moles.

Explanation:

Given,

the weight of CO₂ (w) is 22 gm.

The number of molecules removed (n) = 3 × 10²² molecules.

To find,

The amount of weight and moles of CO₂ left.

Calculation,

The number of moles of 22 gm of CO₂ is

n = 22/44

⇒ n = 0.5

We know that 1 mole of CO₂ contains 6.023 × 10²³ molecules. So 0.5 moles contain 3.061 × 10²³ molecules.

Now if 3 × 10²² molecules are taken out of 3.061 × 10²³ molecules, then the number of molecules left is:

3.061 × 10²³ molecules - 3 × 10²² molecules. = 27.61 × 10²² molecules.

Now if 6.023 × 10²³ molecules contain 1 mole, then 2.761 × 10²³ molecules contain 0.46 moles.

Now the weight of the CO₂ left is:
w = n × GMW

⇒ w = 0.46 × 44

⇒ 20.17 grams.

Therefore, the amount of CO₂ and the moles of CO₂ left is 20.17 grams and 0.46 moles.

#SPJ2