Question

From 280 mg of nitrogen 6.022 into 10 to the power 20 molecules are removed how many moles of nitrogen are left

Answer 1

Answer:

0.01899966777 mol

Explanation:

(14×1000) mg of nitrogen = 6.02×10^23

280 mg of nitrogen = ( 6.02×10^23×280)/(14×1000)

= 1.204×10^22

The molecules of nitrogen that are left

={ 1.204×10^22 – 6.022×10^20 }

= 1.14378×10^22

6.02×10^23 molecules of nitrogen = 1mol

1.14378×10^22 molecules of nitrogen =( 1.14378×10^22) / 6.02×10^23

=0.01899966777 mol