Question

FROM 32 G SULFUR ATOM 3.011*10^23 ATOMS WERE REMOVED WHAT IS THE WEIGHT OF THE REMAINING SULFUR ?

Answer 1

Here is the answer of your question:

Answer:

=16.035 g/mol

Explanation:

Sulfur has a molar mass of (approximately) 32g, so 1 mol of sulfur weighs 32 g. 32g/(32g/mol)=1 mol=x.(1 mol is just 6.02*10^23 atoms).Remaning sulphur atom= (6.02*10^23)-(3.011*10^3) =(0.011*10^3)

=0.5 atoms of 1mol of 1 mole of S = 32.07 g/molSo = 0.5 atoms

=0.5×32.07

=16.035 g/mol

Answer 2

16.035 is answer.......