Question

From 320 gm of S*O_{2} sample, 80 gm of S*O_{2} is removed. So calculate the number of moles of S*O_{2} present in remaining sample?​

Answer 1

Answer:

molecular mass of so2= 32+32=64 gm

$no \: f \: moles \: of \: so2 \: sample = \frac{given \: mass}{molecuar \: mass} = \frac{320}{64} = 5moles \\ no \: of \: moles \: of \: so2 \: removed = \frac{given \: mass}{molecular \: mass} \\ = \frac{80}{64} = \frac{5}{4} = 1.25moles \\ moles \: of \: so2 \: present \: in \: remaining \: sample = 5 - 1.25 = 3.75moles$