from 320 mg of O2 X mg of O2 is removed if 6.02×10^20 molecules of O2 are left then X will be
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Answered by
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Oxygen is a diatomic molecule= O2 = (16x2) = 32 g in one mole
As we know,
32 g of O2 =1 mol = 6.023x1023
Therefore, 320mg = 0.32g = 0.01 mol = 6.023x1021
From this, 6.023x1020 moles are removed = 0.001 moles
Therefore remaining moles are 0.01-0.001 =0.009 moles remain
Answered by
3
Answer:
9× 10^-3 moles
Explanation:
hope it helps
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