Question

from 320mg of o2 6.023*10^23 molecules removed then find the no.of moles 9*10^-3
remianed

Answer 1

Answer:

maom

Explanation:

from 320mg of o2 6.023*10^23 molecules removed then find the no.of moles 9*10^-3

remianed

Answer 2

Answer:

32g of O²

=1mol=6.023×10²³ molecules

∴320mg=0.32g=0.01mol=6.023×10²¹

From this 6.023×10²⁰

moles are removed= 0.001 moles

∴ Remaining= 0.01−0.001=0.009 moles

$= 9 \times {10}^{ - 3}$

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