From 4.2 J of work done what amount of heat can we
get?
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Answer:
Q=7.77×10^4J
Explanation:
Heat required = heat required to bring to 10°C +latent heat for conversion of ice to water+heat require to raise the water temperature by 100°C
=Q=mcΔT for temperature change in same phase
=Q=mL for phase change at same temperature.
=Q=100×2.1×10+100×336+100×4.2×100
=Q=7.77×10^4J
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