Computer Science, asked by lekharaval13, 4 months ago

From 5 boys and 4 girls a team of 3 boys and two girls can be formed by

options

(a) 60 ways.
(b) 50 ways
(c) 40 ways
(d) 30 ways​

Answers

Answered by rupaaalwani
0

Answer:

d) should be the right answer of your question

Answered by Anonymous
0

Answer:

hello,

Explanation:

given :

total boys=5

total girls=4

to find:

the number of ways in which a team of 3 boys and 2 girls can be formed

solution:

for 3 boys:

we have to select 3 boys out of 5

so , n=5 and r=3

number of ways =  C_{r} ^{n}

number of ways   = C^{5} _{3}

number of ways =  \frac{5!}{3!(5-3)!}

number of ways = \frac{5!}{3!X2!}

number of ways = 10

for 2 girls:

we have to select 2 girls out of 4

so, n=4 and r=3

number of ways = C_{r} ^{n}

number of ways  =  C^{4}_ {2}

number of ways = \frac{4!}{2!(4-2)!}

number of ways = \frac{4!}{2!X2!}

number of ways=6

hence total number of ways= 10 X 6

                                                =   60

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(a) 60 ways.

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hope it helps you

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@ItzSnowySecret07

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