Math, asked by pikang, 1 month ago

From 5 CAS, 4 CED, and 3 CEIT students, a committee consisting of 3 CAS, 2 CED, and 1 CEIT student is to be formed. In how many ways can this be done if one particular CED student must be in the committee?

Answers

Answered by amitnrw
0

Given : From 5 CAS, 4 CED, and 3 CEIT students, a committee consisting of 3 CAS, 2 CED, and 1 CEIT student is to be formed.

To Find :  In how many ways can this be done if one particular CED student must be in the committee

Solution:

CAS  = 5 students

3 to be selected  in ⁵C₃  = 10 ways

CED = 4 students

one particular CED student  is already fixed

Hence 1  to be selected  from remaining 4 - 1 = 3

1 to be selected  in ³C₁  = 3 ways

CEIT   = 3 students

1 to be selected  in ³C₁  = 3 ways

Total Ways  = 10 * 3 * 3  = 90

90 ways this can be done

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