From 5 CAS, 4 CED, and 3 CEIT students, a committee consisting of 3 CAS, 2 CED, and 1 CEIT student is to be formed. In how many ways can this be done if one particular CED student must be in the committee?
Answers
Given : From 5 CAS, 4 CED, and 3 CEIT students, a committee consisting of 3 CAS, 2 CED, and 1 CEIT student is to be formed.
To Find : In how many ways can this be done if one particular CED student must be in the committee
Solution:
CAS = 5 students
3 to be selected in ⁵C₃ = 10 ways
CED = 4 students
one particular CED student is already fixed
Hence 1 to be selected from remaining 4 - 1 = 3
1 to be selected in ³C₁ = 3 ways
CEIT = 3 students
1 to be selected in ³C₁ = 3 ways
Total Ways = 10 * 3 * 3 = 90
90 ways this can be done
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