Question

From 5 CAS 4CED and 3 CEIT students a committee consisting 3 CAS 2CED and 1 CEIT students is to formed in how Manny way can this to be done if two particular CED student must be in the committee?​

Answer 1

Given : From 5 CAS, 4 CED, and 3 CEIT students, a committee consisting of 3 CAS, 2 CED, and 1 CEIT student is to be formed.

To Find :  In how many ways can this be done if two particular CED student must be in the committee

Solution:

CAS  = 5 students

3 to be selected  in ⁵C₃  = 10 ways

CED = 4 students

two particular CED student  Hence  1 way

CEIT   = 3 students

1 to be selected  in ³C₁  = 3 ways

Total Ways  = 10 * 1 * 3  =30

30 ways this can be done

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