Question

From 5 different green balls, four different blue balls and three different red balls, how many combinations of balls can be chosen taking at least one green and one blue ball

Answer 1

hi hope 10 will be the answer

Answer 2

Answer:

Step-by-step explanation:

Total combination of balls = 2^12 Combination of balls with no green balls = 2^7 Combination of balls with no blue balls = 2^8 Combination of balls with no blue balls  and no green balls = 2^3

Required combination = 2^12 - 2^7 - 2^8 + 2^3 = 3720.