Question

From 64 g of ch4,6.023×10^23no of molecules removed how many moles of ch4 left

Answer 1

Answer:

3 moles of ch4 are left..

Answer 2

Correct question

From 64g of CH₄, 6.023×10²³ no of molecules are removed. How many moles of CH₄ are left.

Given:-

→Mass of CH₄ (Methane) = 64g

→Number of molecules removed = 6.023×10²³

To find:-

→Number of moles of CH₄ left

Solution:-

•Avogadro number = 6.023×10²³

Molar mass of CH₄ i.e. Methane:-

= 12+1×4

= 16g

Firstly,let's calculate the number of moles in 64 g CH₄.

No of moles = Given mass/Molar mass

= 64/16

= 4 moles

Hence,4 moles are there in 64g of CH₄.

Now,let's calculate the number of moles removed from 64g CH₄.

No of moles:-

No of molecules/Avogadro number

= 6.023×10²³/6.023×10²³

= 1 mole

Hence,1 mole has been removed.

So we got that, from 4 moles of CH₄, 1 mole has been removed.

∴Number of moles left:-

= 4-1

= 3 moles

Thus, 3 moles of CH₄ are left.