Question

from 7p+11q-2r+9 subtract 15-8p+6r-4q​

Answer 1

ANSWER

Given: 6p+4q−r+3,2r−5p−6,11q−7p+2r−1 and 2q−3r+4

To add the given terms we have to add coefficient of like terms:

∴(6p+4q−r+)3+(2r−5p−6)+(11q−7p+2r−1)+(2q−3r+4)

=(6−5−7+0)p+(4+0+11+2)q+(−1+2+2−3)r+(3−6−1+4)

=−6p+17q+0r+0

=17q−6p

Answer 2

Answer:

7p+11q−2r+9)−(15−8p+6r−4q)

⟹7p+11q−2r+9−15+8p−6r+4q

⟹

15p+19q−8r−6

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