Question

From A 100m height a boy throws a stone to ground with 100m/s ..another one from going throws a stone to up with 25m/s..the meeting point of two stones is?

Answer 1

They’ll meet after time
t = Relative Distance/Relative Velocity
= 100 m / [(0 + 25) m/s]
= 4 second

Distance covered by 1st stone in 4 seconds is
S = ut + 0.5at²
= 0 + [0.5 × 9.8 m/s² × (4 s)²]
= 78.4 m

Meeting point of two stones is 78.4 m from top (or) 21.6 m from bottom.

Answer 2

Answer:

sorry..

i dont know answer!!✌