Question

From a 20 m high fall in a reservoir, nearly 25 metric tonnes of water fall per second. Calculate the equivalent power if 40% of this energy is lost and the rest converted into electrical energy.​

Answer 1

Explanation:

Height h = 20 m

Mass of water = 25 metric tonnes = 25000 kg

Time = 1 sec

$power \: = \frac{work \: done}{time} = \frac{mgh}{t} \\ = \frac{25000 \times 9.8 \times 20}{1} \times \frac{40}{100} = 1.96 \times {10}^{6}$

Answer 2

Answer:-

2 x 10^6 J

Explanation:-

height=20m

mass=2.5 x 10

g=10m/s^2

time=1s

Power=Work/time

=mgh/t

=(2.5 x 10^4 x 10 x 20)/1

=5 x 10^6J

5 x 10^6x 40/100=2 x 10^6