Question

From a 22​-foot roll of rubber​ hose, a person cuts lengths of 6 and three eighths
​feet, 6 and one half
​feet, and 4 and one fourth
feet. How much hose is left on the​ roll?

Answer 1

Answer:

Total = 22

he cut few amounts

adding them,

$6 \frac{3}{8} + 6 \frac{1}{2} + 4 \frac{1}{4} \\ = \frac{51}{8} + \frac{13}{2} + \frac{17}{4} \\ = \frac{51 + 52 + 34}{8} \\ = \frac{137}{8}$

remaining hose

$= 22 - \frac{137}{8} \\ = \frac{176 - 137}{8} \\ = \frac{39}{8} \\ = 4 \frac{7}{8}$