From A= 3a+5b-8c-29, find the value of A when a=18, b=0 and c=-3
Answers
Answered by
29
here
a=18,b=0,c=-3
A=3a+5b-8c-29
A=3×18+5×0-8×-3-29
A=54+24-29
A=78-29
A=49
a=18,b=0,c=-3
A=3a+5b-8c-29
A=3×18+5×0-8×-3-29
A=54+24-29
A=78-29
A=49
Answered by
18
Answer:
49
Step-by-step explanation:
A= 3a + 5b - 8c - 29
A= 18, b= 0 and c = - 3
A= ( 3×18) + ( 5×0) -8×-3 -29
A = 54 +24-29
A= 78 -29
A= 49
Similar questions