Question

From a bag containing 10 red , 4 blue and 6 black balls , a ball is drawn at random . find the probability of drawing :a red ball , a blue or black ball , not a black ball

Answer 1

Answer:

Total outcome = 20

Favorable outcomes = (1, 2, 3, 4, 5, 6, 7, 8, 9, 10)

P (Red ball) = 10 / 20 = 1 / 2

Favorable outcomes = (1, 2, 3, 4, 5, 6, 7, 8, 9, 10)

P (Blue or black ball) = 10 / 20 = 1 / 2

Favorable outcomes = (1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14)

P (Not a black ball) = 14 / 20 = 7 / 10

HOPE THAT IT WAS HELPFUL!!!!

MARK IT THE BRAINLIEST IF IT REALLY WAS!!!!

Answer 2

Answer:

here is ur answer mate

Step-by-step explanation:

probability of drawing a red ball = 10/20 = 1/2

probability of drawing a blue ball = 4/20 = 1/5

probablity of drawing a black ball = 6/20 = 3/10

probability of drawing not a black ball = 14/20 = 7/10