Question

from a bag containing 4 white and 6 black balls, 2 balls are drawn at random. if the balls are drawn one after the other without replacement. find the probability
1. both are white
2. both are black
3. first one is white and second one is black
4. one is white and other is black​

Answer 1

Answer:

Probability =Number of favourable outcomes/Total number of outcomes.

Here,Favourable outcomes are (B, B), (W, W), (B, W), (W, B).

Total number of outcomes=4

1.P=1/4

2.P=1/4

3.P=1/4

4.P=1/4

Hope it helps you dear...