Math, asked by jaiveer6, 1 year ago

From a bag containing 5 red, 8 black and
7 blue balls, a ball is selected at random. Find
the probability that (i) it is not a red ball (ii) it
is not a blue ball.​

Answers

Answered by vanshgenius2004
14

Total no. of balls = 20

No. of blue balls = 7

No. of blue balls = 7No. of red balls = 5

No. of blue balls = 7No. of red balls = 5No. of black balls = 8

No. of blue balls = 7No. of red balls = 5No. of black balls = 8 (1) P( it is not a red ball ) = No. of blue and black balls / Total no. of balls

= 15 / 20

= 3 / 4

(2) P( it is not a blue ball ) = No. of black and red balls / Total no. of balls

= 13 / 20

Answered by neha2361
5

Answer:

1. The probability not a red ball is = 15\ 20

2. The probability not a blue ball is = 13\20

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