From a bag containing 5 red, 8 black and
7 blue balls, a ball is selected at random. Find
the probability that (i) it is not a red ball (ii) it
is not a blue ball.
Answers
Answered by
14
Total no. of balls = 20
No. of blue balls = 7
No. of blue balls = 7No. of red balls = 5
No. of blue balls = 7No. of red balls = 5No. of black balls = 8
No. of blue balls = 7No. of red balls = 5No. of black balls = 8 (1) P( it is not a red ball ) = No. of blue and black balls / Total no. of balls
= 15 / 20
= 3 / 4
(2) P( it is not a blue ball ) = No. of black and red balls / Total no. of balls
= 13 / 20
Answered by
5
Answer:
1. The probability not a red ball is = 15\ 20
2. The probability not a blue ball is = 13\20
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