From a bag containing 8 green and 5 red balls,three are drawn one after the other .the probability of all three balls beings green if the balls drawn are replace before the next ball pick and the balls drawn are not replaced , are respectively.
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From a bag containing 8 green and 5 red balls.
Therefore total balls are 8+5=13
three drawn one after the other.
the probability of all three balls beings green if the balls drawn are replace before the next ball pick = (8/13)(8/13)(8/13)
= 512/2197
the probability of all three balls drawn are not replaced (8/13)(7/12)(6/11)
= 336/1716
= 28/143
Therefore total balls are 8+5=13
three drawn one after the other.
the probability of all three balls beings green if the balls drawn are replace before the next ball pick = (8/13)(8/13)(8/13)
= 512/2197
the probability of all three balls drawn are not replaced (8/13)(7/12)(6/11)
= 336/1716
= 28/143
Answered by
0
Answer:
512/2190, 336/1716
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