Physics, asked by vihaanbelliappa, 7 months ago

from a ballon acendind vertically with velocity of 18ms^-1,a bag is released .it reaches the ground in 12 seconds . calculate the height of the ballon when the bag was released and the bag when it reaches the ground.

Answers

Answered by mbakshi37

0

Answer:

720 m

H Balloon = Ho+ V T

H Balloon = Ho + 12x18 = 216+ Ho

H Balloon = 216+ Ho

H0 =-UT + 1/2 a t^2

H0 =-12x18+ 1/2x10x144

H0= 720-216=504

H Baloon at 12 sec = 216+504= 720 m

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