Question

from a ballon acendind vertically with velocity of 18ms^-1,a bag is released .it reaches the ground in 12 seconds . calculate the height of the ballon when the bag was released and the bag when it reaches the ground.

Answer 1

Answer:720 m

H Balloon = Ho+ V T

H Balloon = Ho + 12x18 = 216+ Ho

H Balloon  = 216+ Ho

H0 =-12x18+ 1/2x10x144

H0= 720-216=504

H Baloon at 12 sec = 216+504= 720 m