from a balloon vertically above a straight road the angle of depression of two cars on the same side at an instant are found to be 45degree and 60degree. if the cars are 100meters apart find the height of the balloon
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Let the two cars be at points C and D.
That is distance between the cars, CD = 100 m
Let BD = d
Hence BC = (100 – x) m
Let the height of the balloon be AB = ‘h’ m
In right ΔABD, θ = 45°
In right ΔABC, θ = 60°
⇒ 100√3 – √3h = h
⇒�100√3 = √3h + h = h(√3 + 1)
∴ h = 50√3(√3 + 1) m
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