Question

From a battery of potential difference 12.0 volt,current 2.0 ampere flows through a wire for 30 minutes . Find
1. The electrical energy supplied by the battery ,and
2. The power spent

Answer 1

Answer:

Question

From a battery of potential difference 12.0 volt,current 2.0 ampere flows through a wire for 30 minutes . Find

1. The electrical energy supplied by the battery ,and

2. The power spent

Given

1. Potential difference, V ↦ 12.0 volt
2. Current, I ↦2.0 ampere
3. Time,T ↦ 30 min = 30×60 = 1800 s

Explanation:

$\underline{\underline{\maltese\:\:\textbf{\textsf{Solution}}}}$

• Energy supplied ,W

$\underline { \boxed{ \sf{ \blue \: W = \bf \: VIT}}}$

$↦12.0 \times 2.0 \times \times 1800 = 43200 \: j$

• Power, P

$\underline { \boxed{ \sf{ \blue \: P = VI \bf \: }}}$

$↦12.0 \times 2.0 = 24.0 \: w$

Answer 2

Given

• From a battery of potential difference 12.0 volt current 2.0 ampere flows through a wire for 30 minutes.

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To Find

• The electrical energy supplied by the battery
• The power spent.

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Solution

(i) So we know that,

Energy = Power × Time (in seconds)

Here the power = voltage × current

So let's find the power first.

Power = 12.0 × 2.0 = 24.0

Now let's convert minutes into seconds.

30 minutes = 30 × 60 = 1800 seconds

Now with the obtained power and time in seconds, we'll find the electrical energy supplied by the battery.

Energy = 24 × 1800

Energy = 43200 joules

∴ The electrical energy supplied by the battery is 43200 joules.

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(ii) Power = Voltage × Current

Power = 12.0 × 2.0  

Power = 24.0 watt

∴ The power spent is 24.0 watt.

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