Question

from a box of 6red ball and 5orange balls 4balls are to be selected what is the probability that the selected balls will have the number of red balls less than that of orange balls ​

Answer 1

Answer:

3/4

Step-by-step explanation:

16 chances are possible to take 4 balls from 11 balls

2*2*2*2=16(because when we take a ball it can be red or orange)

the chance that when we take we get orange balls is

O,R,R,R;O,O,R,R;O,O,O,R;O,O,O,O

That is 4 ways on 16

so 16-4=12

12/16=3/4

Answer 2

$\huge\mathfrak\color{Orange}{Answer}$

$\mathcal\pink{Event(P)--To\:get\:more\:red\:balls\:than\:that\:of\:Orange\:balls}$

$Favourable\:Outcomes=\:6$

$Total\:possible\:outcomes=\:6+5=>\:11$

$Probability=Favourable\:Outcomes/Total\:Possible\:Outcomes$

$P=6/11$

•°• So,the probability of getting red balls more than that of Orange balls is 6/11