Question

From a bridge, 25m high the angle of depression of a boat is 45 degrees. Find the horizontal distance of the boat from the bridge.​

Answer 1

Answer:

25m

Step-by-step explanation:

Let the angle B be 45 degree (Angle of depression)

when B is 45 degree  then angle A will also be 45 degrees.

Let a be the height of the bridge=25 m(given)

Let b be the distance from the boat to the bridge.

therefore tan teta=opposite side/adjacent side .(teta=45degrees)   tan 45 degree= a/b

                              (tan 45 degree=1) --(standard unit)

      then    tan 45 degrees = a/b

                =         1                 =25/b

                  therefore on solving , b=25m which is the distance from boat to the bridge.

(A suggestion: plz draw a line horizontal to the angle B which is not present in the picture attached to this)(then the angle of depression in this question would be between the horizontal line drawn and the side c.) (neglect side c in solving this question)

Hope it helps:)

Answer 2

Answer:

25m

Step-by-step explanation:

Let the angle B be 45 degree (Angle of depression)

when B is 45 degree  then angle A will also be 45 degrees.

Let a be the height of the bridge=25 m(given)

Let b be the distance from the boat to the bridge.

therefore tan teta =opposite side/adjacent side .(teta=45degrees)   tan 45 degree= a/b

(tan 45 degree=1) --(standard unit)

tan 45 degrees = a/b 1  =25/b

therefore on solving , b=25m which is the distance from boat to the bridge.

(A suggestion: plz draw a line horizontal to the angle B which is not present in the picture attached to this)(then the angle of depression in this question would be between the horizontal line drawn and the side c.) (neglect side c in solving this question)

Hope it helps:)