Question

From a building three objects are dropped. First object with velocity u = 0 and time t1 and another object with velocity u and time t2 and another object with velocity u and time t3. Find the relationship between t1, t2 & t3

Answer 1

S=ut-(gt*t)/2 S=-(gt^2)/2.....u=0 S=ut(2)-(gt(2)^2)/2.....u=u S=u(t3)-(gt^2(3))/2.....u=u Equating -(gt^2)/2.=gt(2)^2)/2.=(gt(3)^2)/2 (T1^2)=t2^2=t3^2