Question

From a bus stand in Bangalore, if we buy 2 tickets to Malleswaram and 3 tickets to
Yeshwanthpur, the total cost is Rs. 46; but if we buy 3 tickets to Malleswaram and 5
tickets to Yeshwanthpur the total cost is Rs. 74. Find the fares from the bus stand to
Malleswaram and to Yeshwanthpur by elimination method. Ans (Rs. 8, Rs. 10)
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Answer 1

Answer:

46 divided by 3 = 23 , 74 divided by 5 =14 add each answer 23+14=37

Answer 2

Answer:

Bus fare from bus stand to Malleswaram = Rs. 8

Bus fare from bus stand to Yeshwanthpur  = Rs. 10

Step-by-step explanation:

Let 'x' be the bus fare to Malleswaram and 'y' be the bus fare to Yeshwanthpur from bus stand

Since the cost of 2 tickets to Malleswaram and 3 tickets to

Yeshwanthpur is Rs. 46; we have

2x +3y = 46 -------------------(1)

Again the cost of  3 tickets to Malleswaram and 5tickets to Yeshwanthpur is Rs. 74; we have

3x + 5y = 74 -----------------(2)

(1) ×3  →   6x + 9y = 138 -----------------(3)

(2) ×2 →  6x + 10y = 148 ----------------(4)

(4) - (3) → 10y - 9y = 148 -138

y = 10

Substituting the value of 'y' in equation (1) we get,

2x + 30 = 46

2x = 16

x = 8

∴Bus fare from bus stand to Malleswaram = Rs. 8

Bus fare from bus stand to Yeshwanthpur  = Rs. 10

#SPJ3