Question

From a certain point above the ground, an object is projected vertically upward. It reaches the ground in a time t1. From the same point, the object is then projected vertically downward with the same initial speed. It reaches the ground in a time t2. If the same object is dropped from the same point, it will reach the ground in a time

Answer 1

Answer: t = √(t₁t₂)

Step-by-step explanation:

Let say Ball thrown with Speed V

thrown vertically downwards with V it reaches the ground in time t₂ S = Vt₂ + (1/2)g(t₂)²

thrown vertically upwards from the top of a tower it reaches the ground in time t1

Time taken to come at same point = t₁ - t₂

Time taken to teach top = (t₁ - t₂)/2

Velocity at top = 0

0 = V-g(t₁- t₂)/2

=> V = g(t₁ - t₂)/2

S = t₂g(t₁ - t₂)/2 + (1/2)g(t₂)²

S = gt₁t₂/2

V

if fall freely then

S = (1/2)gt²

Explanation:

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Answer 2

this is the answer

height of point b is gt1t2/2