from a circle aluminium sheet of diameter 8 cm, a circle of radius 3 cm is removed. find the area of the remaining sheet.
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Answered by
0
Step-by-step explanation:
D=8cm
R=4cm
area of bigger circle = pi×R^2
=22/7×4×4
=352/7 cm^2
r=3cm
area of smaller circle =22/7×3×3
=198/6 cm^2
therefore, remaining area
=352/7-198/7
=54/7
=7.71 cm^2
Answered by
2
Answer:
area of remaining sheet= area of big circle-area of small circle
=pi r1²-r2²
=pi 16-9
=pi 7
=22/7 × 7
=7 cm²
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