Question

From a circle of radius a an isosceles Right angled triangle with the hypotenuse as the diameter of the circle is removed .the distance of the centre of gravity of the remaining position from the centre of the circle is

Answer 1

mdisc=σπa2  mΔ=−σ×12×(2a)×a=−σa2 ycm=m1y1+m2y2m1+m2=σπa2(0)+(−σa2)(a/3)σa2(π−1)=a3(π−1) (answer)  

Answer 2

Answer:

Explanation:

The com will shift only in y direction thus only y axis will be dealt