From a circular aluminium sheet of radius 14cm, a sector of angle 45° is removed. Find the percentage of the area of the sector removed. Use formula ∅/360°. Explain with statements.
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Answered by
11
Percentage of the area is independent of the Radius.
area removed = (45°/360°)×100
=100/8 = 12.5%
In detail,
area of whole circle = π r² = π ×(14)² = 196 π cm²
area removed = 196 π ×(45°/360°) = 24.5 π cm²
percent of area removed = (24.5π)/(196π)×100 = 12.5%
area removed = (45°/360°)×100
=100/8 = 12.5%
In detail,
area of whole circle = π r² = π ×(14)² = 196 π cm²
area removed = 196 π ×(45°/360°) = 24.5 π cm²
percent of area removed = (24.5π)/(196π)×100 = 12.5%
Answered by
2
Answer:
21.5%
Step-by-step explanation:
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