From a circular card sheet of radius 14 cm,2 circles of radius 3.5cm and a rectangle of length 3cm and a breadth is 1 cm is removed.find the area of remaining sheet .(pi=22÷7)
Answers
total area= πr²
=22/7*196=616 cm²
r2= 3.5 cm
area of the small circles= 2*πr²=2*12.25*22/7=77 cm²
length of rectangle=3
breadth=1
area =lb=3 cm²
area of the small circles+area of rectangle=77+3=80 cm²
remaining area=616-80=536 cm²
Given :- From a circular card sheet of radius 14 cm,2 circles of radius 3.5cm and a rectangle of length 3cm and a breadth is 1 cm is removed.find the area of remaining sheet .? (pi=22÷7)
Solution :-
we know that,
- Area of circle = π * (radius)² .
- Area of rectangle = Length * Breadth .
so,
→ Area of remaining sheet = Area of seat - (Area of 2 circles + Area od rectangle.)
Putting all values now, we get,
→ Area of remaining sheet = π(14)² - [2*{π*(3.5)²} + 3 * 1]
→ Area of remaining sheet = 22*14*2 - [2*22*3.5*0.5 + 3]
→ Area of remaining sheet = 616 - (77 + 3)
→ Area of remaining sheet = 616 - 80
→ Area of remaining sheet = 536 cm². (Ans.)
Hence, Area of remaining sheet is 536 cm².
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