Question

From a circular card sheet of radius 14 cm, two circle of radius 3.5 cm and rectangle of length 3cm and breath 1cm are removed. Find area of remaining sheetπ22/7

Answer 1

We have,
radius of the circular sheet=14cm
it's area=πr^2
=22/7*(14)^2
=22/7*14*14
=616cm^2

Now ,two circles cut from the circular sheet card of radii=3.5cm

it's area=πr^2
=22/7*(3.5)^2
=38.5cm^2
so the area of the other circle =38.5cm^2

and also cut rectangle of ,
length=3cm
breadth=1cm
area of rectangle =length*breadth
=3cm*1cm
=3cm^2
now total area of the two circles and one rectangle cut down from the circular card sheet=38.5cm^2+38.5cm^2+3cm^2
=80cm^2

remaining part of the circular card sheet=Area of card sheet-total area of two circles and rectangle
=616cm^2-80cm^2
=536cm^2

Answer 2

$\large{\bf{\green{\underline{\underline{♧AnsWer♧}}}}}$

Area of outer circle =$\pi {r}^{2} \\ = \frac{22}{7} \times 14 \times 14 \\ = 22 \times 28 = 616 cm²</p><p>⠀⠀⠀⠀</p><p>\\ \\ area \: of \: inner \: circle \: = 2 \times \pi {r}^{2} \\ \: = \: 2 \times \frac{22}{7} \times 35 \times 35 \\ = 22 \times 3.5 \\ = 77 {cm}^{2} \\ \\ </p><p>area \: of \: rectangle = \: l \times b \\ area</p><p> \: of \: whole \: circle \: -</p><p> \: ( \: area </p><p>\: of \: the</p><p> \: both \: circles \: </p><p>+ </p><p>\: area \: of</p><p> \: rectangle</p><p> \: ) \: = \: area </p><p>\: of</p><p> \: remaing \: sheet. \\ = 616 \: - \: ( \: 77 + 3) \\</p><p> = 616 - 80 = </p><p> {536cm}^{2} ....$