Question

From a circular card sheet of radius 14 cm, two circles of radius 3.5 cm and a rectangle of length 3 cm and breadth 1cm are removed. (as shown in the adjoining figure). Find the area of the remaining sheet. (Take π = $\frac{22}{7}$

Answer 1

Answer:

Area of bigger Circle is π R²

= 22/7 ×14cm ×14cm

=610 cm²

area of 2 smaller circles is πr²

= 2(22/7 × 3.5cm × 3.5cm)

= 2 ×1.75cm²

= 3.5cm²

now area of rectangle= L× B

= 3cm×1cm

= 3cm²

on removing the area of two small circle and rectangle from the bigger Circle

= 610cm² - (3.5cm²+3cm²)

= 610cm²-6.5cm²

= 603.5cm². #ans

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Answer 2

$\huge\mathfrak{\underline{Correct\:question}}$

From a circular card sheet of radius 14 cm, two circles of radius 3.5 cm and a rectangle of length 3 cm and breadth 1cm are removed. (as shown in the adjoining figure). Find the area of the remaining sheet. (Take π = 22/7)

_____________________________

Given that:-

• Radius of the circular card sheet = 14 cm

• Radius of the two small circle = 3.5 cm

• Length of the rectangle = 3 cm

• Breadth of the rectangle = 1 cm

To find:-

• The area of remaining sheet.

Answer:-

$\bold{STEP-BY-STEP-EXPLANATION}$

From the question,

First we have to find out the area of circular card sheet, two circles and rectangle to find out the remaining area.

Now,

Area of the circular card sheet = πr2

= 22/7 × 142

= 22/7 × 14 × 14

= 22 × 2 × 14

= 616 cm^2

Area of the 2 small circles = 2 × πr2

= 2 × (22/7 × 3.52)

= 2 × (22/7 × 3.5 × 3.5)

= 2 × ((22/7) × 12.25)

= 2 × 38.5

= 77 cm^2

Area of the rectangle = Length × Breadth

= 3 × 1

= 3 cm^2

Now,

The area of the remaining part =

Card sheet area – (area of two small circles + rectangle

area)

= 616 – (77 + 3)

= 616 – 80

= 536 cm^2

Therefore, area of remaining sheet = 536 cm^2

#BAL

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