Question

From a circular card sheet of radius 14 cm, two circles of radius 3.5 cm and a rectangle of lenght 3cm and breadth 1cm are removed.Find the area of the remaning sheet.​

Answer 1

Answer:

Find an answer to your question From a circular card ... area of 2 circles = 2*πr² =2*22/7*3.5*3.5 =77 cm² area of rectangle = 3*1 =3 cm ² area of remaining sheet of length 3 cm and breadth 1 cm are removed find the area of the ... radius and a rectangle of 3cm Length and 1 cm breadth ... Hence. the area of remaining sheet is

Answer 2

Answer:

Area of the circle =

$\pi \: r {}^{2}$

22/7×14×14=616cm2

Area of the new circle=

$\pi \: r {}^{2}$

22/7×3.5×3.5=38.5cm2

Area of the rectangle= l×b

3×1=3cm2.

Area of the remaining sheet = Area of the sheet-(area of the new circle + area of the rectangle.)

Area of the remaining =616-(38.5+3)

616-41.5=574.5cm2

The area of the remaining sheet is 574.5cm2

Step-by-step explanation:

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