Question

From a circular card sheet of radius 14 cm, two circles of radius 3,5 cm and a
rectangle oflength 3 cm and breadth 1cm are removed. (as shown in the adjoining
figure). Find the area of the remaining sheet. (Take te= )
22​

Answer 1

Answer:

506.3 cm^2

Step-by-step explanation:

area of circular card sheet = πr^2

=(22/7)×14×14

=616cm^2

area of circle removed

=πr^2

=(22/7)×3×3

=28.2cm^2

area of 2nd circle removed

=πr^2

=(22/7)×5×5

=78.5cm^2

area of rectangle removed

=l×b

=3×1

=3cm^2

so area remaining will be

=area of circular card sheet - (area of 2 circles + area of rectangle )

=616-(28.2+78.5+3)

=616-109.7

=506.3cm^2

Answer 2

$\large{\bf{\red{\underline{\underline{AnsWer}}}}}$

Area of outer circle =$\pi {r}^{2} \\ = \frac{22}{7} \times 14 \times 14 \\ = 22 \times 28 = 616 cm²</p><p>⠀⠀⠀⠀</p><p>\\ \\ area \: of \: inner \: circle \: = 2 \times \pi {r}^{2} \\ \: = \: 2 \times \frac{22}{7} \times 35 \times 35 \\ = 22 \times 3.5 \\ = 77 {cm}^{2} \\ \\ </p><p>area \: of \: rectangle = \: l \times b \\ area</p><p> \: of \: whole \: circle \: -</p><p> \: ( \: area </p><p>\: of \: the</p><p> \: both \: circles \: </p><p>+ </p><p>\: area \: of</p><p> \: rectangle</p><p> \: ) \: = \: area </p><p>\: of</p><p> \: remaing \: sheet. \\ = 616 \: - \: ( \: 77 + 3) \\</p><p> = 616 - 80 = </p><p> {536cm}^{2} ....$