Math, asked by maxy2, 1 year ago

from a circular card sheet of radius 14 cm two circles of radius 3.5 cm and rectangle of length 3 cm and 1 cm are removed find the area of remaining sheet

Answers

Answered by rahulprasadpan
13
area of circular card = πr×r
=22/7×14×14
=176
area of 2 circle. =2×πr×r
=2×22/7×3.5×3.5
=77.00 or77
area of rectangle =3×1 =3cm
now.area of sheet =176-77+3=176-80=96
Answered by Anonymous
0

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Area of outer circle =\pi  {r}^{2}  \\   =  \frac{22}{7}   \times 14 \times 14 \\  = 22 \times 28 = 616 cm²</p><p>⠀⠀⠀⠀</p><p>\\  \\ area \: of \: inner \: circle \:  = 2 \times  \pi  {r}^{2}  \\  \:  =  \: 2 \times  \frac{22}{7}  \times 35 \times 35 \\  = 22 \times 3.5 \\  = 77 {cm}^{2}  \\  \\ </p><p>area \: of \: rectangle =  \: l \times b \\ area</p><p> \: of \: whole \: circle \:  -</p><p>  \: ( \: area </p><p>\: of \: the</p><p> \: both \: circles \:  </p><p>+  </p><p>\: area \: of</p><p> \: rectangle</p><p> \: ) \:  =  \: area </p><p>\:  of</p><p> \: remaing \: sheet. \\  = 616 \:  -  \: ( \: 77 + 3) \\</p><p>  = 616 - 80 = </p><p> {536cm}^{2} .....

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