Question

From a circular card sheet of radius 14 cm, two circles of radius 3.5 cm and a rectangle of length 3 cm and breadth 1 cm are removed (as shown in the adjoining figure). Find the area of the remaining sheet. ​

Answer 1

Answer:

Radius of circular sheet(R)=14cm and Radius of smaller circle(r)=3.5cm

Length of rectangle(l)=3cm and breadth of rectangle(b)=1cm

According to question,

Area of remaining sheet=Area of circular sheet−[Area of two smaller circle+Area of rectangle

=πR²-[2(πR²)+(l*b)]

$\frac{22}{7} \times 14 \times 14 -[(2 \times \frac{22}{7} \times 3.5 \times 3.5) - (3 \times 1) ]$

=22×14×2−[44×0.5×3.5+3]

=616−80

=536²cm

Therefore the area of remaining sheet is 536²cm

follow by

Answer 2

$\huge \underline \mathbb \orange{QUESTION}$

From a circular card sheet of radius 14 cm, two circles of radius 3.5 cm and a rectangle of length 3 cm and breadth 1 cm are removed (as shown in the adjoining figure). Find the area of the remaining sheet.

$\huge \underline \mathbb \orange{ANSWER}$

Area of big cycle $= \pi \times (14)² \: cm²$

$= \frac{22}{7} \times 14 \times 14 \: cm²$

$= 44 \times 14 \: cm²$

Area of big cycle $= 616 \: cm²$

Area of 2 circles with radius 3.5cm each$= 2 \times [\pi \times (3.5)²] \: cm²$

$= 2 \times \frac{22}{7} \times 3.5 \times 3.5 \: cm²$

$= 44 \times 1.75 \: cm²$

$= 77 \: cm²$

Area of rectangle $= 3 \times 1 = 3 \: cm²$

Area of remaining sheet (After removing two circles and a rectangle)

=Area of big circle -(Area of 2 circles + Area of rectangle)

$= [616 - (77 + 3)] \: cm²$

$= (616 - 80) \: cm²$

$= 536 \: cm²$

Hence, Area of remaining sheet = 536 cm²

Hope It Helps You!!...