From a circular card sheet of radius 14 cm, two circles of radius 3.5 cm and a rectangle of length 3 cm and breadth 1cm are removed. Find the area of the remaining sheet.
Answers
Answer:
Area of bigger Circle is π R²
= 22/7 ×14cm ×14cm
=610 cm²
area of 2 smaller circles is πr²
= 2(22/7 × 3.5cm × 3.5cm)
= 2 ×1.75cm²
= 3.5cm²
now area of rectangle= L× B
= 3cm×1cm
= 3cm²
on removing the area of two small circle and rectangle from the bigger Circle
= 610cm² - (3.5cm²+3cm²)
= 610cm²-6.5cm²
= 603.5cm². #ans
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Answer:
Radius of the circular sheet = 14 cm
∴ Area = πr square = 227 × 14 × 14 cm square
= 616 cm square
Area of 2 small circles = 2 × πr square
= 2 × 227 × 3.5 × 3.5 cm square
= 77.0 cm square
Area of the rectangle = l × b
= 3 × 1 cm square = 3 cm square
Area of the remaining sheet after removing the 2 circles and 1 rectangle
= 616 cm square – (77 + 3) cm square
= 616 cm square – 80 cm square = 536 cm
Step-by-step explanation:
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