From a circular card sheet of radius 14 cm, two circles of radius 3.5 cm and a rectangle of length 3 cm and breadth 1 cm are removed (as shown in the adjoining figure) find the area of the remaining sheet.
Answers
Radius of circular sheet(R)=14cm and Radius of smaller circle(r)=3.5cm
Length of rectangle(l)=3cm and breadth of rectangle(b)=1cm
According to question,
Area of remaining sheet=Area of circular sheet−[Area of two smaller circle+Area of rectangle]
=πR2−[2(πr2)+(l×b)]
=722×14×14−[(2×722×3.5×3.5)−(3×1)]
=22×14×2−[44×0.5×3.5+3]
=616−80
=536cm2
Therefore the area of remaining sheet is 536cm2.
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Radius of circular sheet(R)=14cm and Radius of smaller circle(r)=3.5cm
Length of rectangle(l)=3cm and breadth of rectangle(b)=1cm
According to question,
Area of remaining sheet=Area of circular sheet−[Area of two smaller circle+Area of rectangle]
=πR 2 −[2(πr 2 )+(l×b)]= 722 ×14×14−[(2×722×3.5×3.5)−(3×1)]
=22×14×2−[44×0.5×3.5+3]
=616−80
=536cm 2
Therefore the area of remaining sheet is 536cm
2
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