Question

from a circular card sheet of radius 14cm, two circle of radius 3.5 cm and rectangle of length 3 cm and breadth 1 cm are removed. ( as shown in the adjoining figure) .find the area of the remaining sheet​

Answer 1

Answer:

• radius of the sheet=14cm

area of the sheet=πr²

22/7×14×14

=616cm²

• radius of the circle=3.5

area of the circle=πr²

22/7×3.5×3.5

77cm²

• area of the rectangle=l×b

3cm×1cm

3cm²

• area of the remaining sheet=616cm²-(77+3)

=536cm²

Answer 2

$\large{\bf{\red{\underline{\underline{AnsWer}}}}}$

Area of outer circle =$\pi {r}^{2} \\ = \frac{22}{7} \times 14 \times 14 \\ = 22 \times 28 = 616 cm²</p><p>⠀⠀⠀⠀</p><p>\\ \\ area \: of \: inner \: circle \: = 2 \times \pi {r}^{2} \\ \: = \: 2 \times \frac{22}{7} \times 35 \times 35 \\ = 22 \times 3.5 \\ = 77 {cm}^{2} \\ \\ </p><p>area \: of \: rectangle = \: l \times b \\ area</p><p> \: of \: whole \: circle \: -</p><p> \: ( \: area </p><p>\: of \: the</p><p> \: both \: circles \: </p><p>+ </p><p>\: area \: of</p><p> \: rectangle</p><p> \: ) \: = \: area </p><p>\: of</p><p> \: remaing \: sheet. \\ = 616 \: - \: ( \: 77 + 3) \\</p><p> = 616 - 80 = </p><p> {536cm}^{2} ....$