Question

From a circular card sheet of radius 14cm two circle of radius 3.5cm and a rectangle of length 3cm and breadth 3cm and breadth 1 cm are removed (as shown in the figure).find the area of the remaining sheet.(take pie= 22/7)​

Answer 1

Step-by-step explanation:

Radius of circular sheet(R)=14cm and Radius of smaller circle(r)=3.5cm

Length of rectangle(l)=3cm and breadth of rectangle(b)=1cm

According to question,

Area of remaining sheet = Area of circular sheet−[Area of two smaller circle + Area of rectangle]

πR² - [2( πr²) + (l×b)]

$\frac{2}{7} \times 14 \times 14 - \\ |(2 \times \frac{22}{7} \times 3.5 \times 3.5) - (3 \times 1) |$

=22×14×2−[44×0.5×3.5+3]

=616−80

=536cm²

Therefore the area of remaining sheet is 536cm²

Answer 2

Answer:

536 cm square is the answer....