Math, asked by bhagwatsinghtalan, 4 months ago

From a circular card sheet of radius 14cm, two circles of radius 3.5cm and a rectangle of lenght 3 cm and breadth 1cm are removed. (as shown in the adjoining figure). Find the area of the remaning sheet.(Take x=22/7)​

Answers

Answered by guptachirag745
1

Answer:

  • yfyfyfyfhfyff6f6f6f2g262y363yeyg3yeg3y33h3uu3u3h3he
Answered by itZzAnshu
2

Question :-

From a circular card sheet of radius 14cm, two circles of radius 3.5cm and a rectangle of lenght 3 cm and breadth 1cm are removed. Find the area of the remaning sheet.(Take π =22/7)

Solution :-

r = 14 cm.

Total area = πr²

= 22/7 × 196 = 616 cm²

r2 = 3.5 cm.

Area of the small circles = 2πr² = 2 × 12.25 ×22/7 = 77 cm²

length of rectangle = 3cm.

breadth = 1cm.

Area of rectangle = lb = 3 × 1 = 3cm²

Area of the small circles + Area of rectangle = 77 + 3 = 80 cm²

Remaining area = 616 - 80 = 536 cm².

Final answer :-

Area of the remaining sheet is 536cm².

Similar questions