From a circular card sheet of radius 14cm, two circles of radius 3.5cm and a rectangle of lenght 3 cm and breadth 1cm are removed. (as shown in the adjoining figure). Find the area of the remaning sheet.(Take x=22/7)
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Question :-
From a circular card sheet of radius 14cm, two circles of radius 3.5cm and a rectangle of lenght 3 cm and breadth 1cm are removed. Find the area of the remaning sheet.(Take π =22/7)
Solution :-
r = 14 cm.
Total area = πr²
= 22/7 × 196 = 616 cm²
r2 = 3.5 cm.
Area of the small circles = 2πr² = 2 × 12.25 ×22/7 = 77 cm²
length of rectangle = 3cm.
breadth = 1cm.
Area of rectangle = lb = 3 × 1 = 3cm²
Area of the small circles + Area of rectangle = 77 + 3 = 80 cm²
Remaining area = 616 - 80 = 536 cm².
Final answer :-
Area of the remaining sheet is 536cm².
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